Define f(x) as the product of two real functions f_(1)(x)=x, x epsilon IR and f_(2)(x)={("sin"1/x, "if", x!=0),(0 , "if", x=0):} as follows f(x)={(f_(1)(x).f_(2)(x), "if", x!=0),(0, "if", x=0):}

Define f(x) as the product of two real functions f_(1)(x)=x, x epsilon

1.	Define f(x) as the product of two real functions f_(1)(x)=x, x epsilon IR and f_(2)(x)={("sin"1/x, "if", x!=0),(0 , "if", x=0):} as follows f(x)={(f_(1)(x).f_(2)(x), "if", x!=0),(0, "if", x=0):}
Answer» Statement-1 is True, Statement -2 is True, Statement -2 is True and Statement -2 is a CORRECT explanation for statement -1. Statement -1 is True, Statement -2 is True and Statement -2 is Not is a correct explanation for Statement -1. Statement -1 is True, Statement -2 is FALSE. Statement -1 is False, Statement -2 is True. Answer :D

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Define f(x) as the product of two real functions f_(1)(x)=x, x epsilon IR and f_(2)(x)={("sin"1/x, "if", x!=0),(0 , "if", x=0):} as follows f(x)={(f_(1)(x).f_(2)(x), "if", x!=0),(0, "if", x=0):}

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