1.

Define f(x) = {{:(x,(0le x le 1)),(2-x,(1 lex le 2)):} Then Rolle's theorem is not applicable to f(x) because

Answer»

F(x) is not DEFINED everywhere on [0, 2]
f(x) is not continuous on [0, 2]
f(x) is not DIFFERENTIABLE on (1, 2)
f(x) is not differentiable on (0, 2)

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