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Define g(x)=int_(-3)^(3)f(x-y)f(y)dy, for all real x, where f(t)={{:(1","0letle1),(0", elsewhere."):} Then |
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Answer» g(x) is not CONTINUOUS everywhere `g(x)=int_(0)^(1)f(x-y)DY` `x-y=t,-dy.dt` `g(x)=int_(x-1)^(x)f(t)dt` `g(x)={{:(0,xle0),(x,0lt x lt1),(2-x,1lexle2),(0,xgt2):}` Now, CHECK yourself |
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