InterviewSolution
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InterviewSolution
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Define `g(x)=int_(-3)^(3)f(x-y)f(y)dy,` for all real x, where `f(t)={{:(1","0letle1),(0", elsewhere."):}` ThenA. g(x) is not continuous everywhereB. g(x) is continuous everywhere but differentiable nowhereC. g(x) is continuous everywhere and differentiable everywhere except at x=0,1D. g(x) is continuous everywhere and differentiable everywhere except at x=0,1,2 |
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Answer» Correct Answer - D Definition can be break as `g(x)=int_(0)^(1)f(x-y)dy` `x-y=t,-dy.dt` `g(x)=int_(x-1)^(x)f(t)dt` `g(x)={{:(0,xle0),(x,0lt x lt1),(2-x,1lexle2),(0,xgt2):}` Now, check yourself |
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