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InterviewSolution
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Define loss of kinetic energy in inelastic collision |
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Answer» Solution :In perfectly inelastic collision, the loss in kinetic energy during collision is transformed to another form of energy like SOUND, thermal, heat, light etc. LET `KE_i` be the TOTAL kinetic energy before collision and `KE_f` be the total kinetic energy after collision. Total kinetic energy before collision, `KE_i = 1/2 m_1u_1^2 + m_2 u_2^2 "" ...(1)` Total kinetic energy after collision, `KE_f = 1/2 (m_1 + m_2) v^2 "" ...(2)` Then the loss of kinetic energy is Loss of KE ,` Delta Q = KE_f - KE_i` ` =1/2 (m_1 + m_2) v^2 - 1/2 m_1 u_1^2 + 1/2 m_2 u_2^2 "" ...(3)` SUBSTITUTING equation ` v = (m_1u_1 + m_2 u_2)/(m_1 + m_2)` in equation (3), and on simplifying (expand v by using the algebra `(a + b)^2 =a ^2 + b^2 + 2ab` we get Loss of KE , ` DeltaQ = 1/2 ((m_1 m_2)/(m_1 + m_2)) (u_1 - u_2)^2` |
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