1.

Define Molarity. If 5.6 g of KOH is present in 250 ml of the solution, calculate the molarity of the solution.

Answer»

Solution : ''The number of moles of SOLUTE dissolved in one litre of the solvent'' is called as Molarity of the solution.
Molarity (M) `=("number of moles of solute")/("Volume of the solvent in Litres")`
If 5.6 G of KOH is present in 250 ML of the solution Number of moles of KOH `= (5.6 g)/(56 mol^(-1))=0.1` moles
Molarity (M) `= ("0.1 moles")/("0.4 Lit")=0.25 "mol Lit"^(-1)` (or) 0.25 M.


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