1.

Define resolving power of microscope. How does it affect when:(i) Wavelength of illuminating radiation decreases?(ii) Diameter of object lens decreases? Give explanation of your answer.

Answer»

The resolving power of a microscope is defined as reciprocal of the smallest distance between two point objects at which they can be just resolved when seen through the microscope.
R.P. of a microscope = \(\frac{1}{d}=\frac{2 n \sin \theta}{\lambda}\)
(i) As R.P. ∝ \(\frac{1}{\lambda}\)
When λ decreases, R.P. increases.
(ii) When the aperture of the objective lens decreases, the semivertical angle θ decreases and hence the resolving power of the microscope increases.



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