Define the probability of an event. A’: ‘card drawn is not a diamo

1.	Define the probability of an event. A’: ‘card drawn is not a diamond’
Answer» For a finite sample space S with equally likely We have n(A) = 13, n(S) = 52 outcomes, probability of an event A is denoted by P(A) = n(A)/n(S), Where n(A) = number of elements in the set A n(S) = number of elements in the set S. Note: (i) If A and B are any two events, then P(A or B) = P(A) + P(B) – P(A and B) i.e., P( A ∪ B) P(A) + P(B) – P(A ∩ B) (ii) If A and B around mutually exclusive, then P (‘A or B’) = P(A) + P(B) i.e., P(A ∪ B) = P(A) + P(P) ∵ A ∩B = ϕ (iii) If A is any event, then P(‘not A’ ) = P(A’) = 1 – P(A)

Define the probability of an event. A’: ‘card drawn is not a diamond’

Answer»

For a finite sample space S with equally likely We have n(A) = 13, n(S) = 52 outcomes, probability of an event A is denoted by P(A) = n(A)/n(S),

Where n(A) = number of elements in the set A n(S) = number of elements in the set S.

Note:

(i) If A and B are any two events, then

P(A or B) = P(A) + P(B) – P(A and B)

i.e., P( A ∪ B) P(A) + P(B) – P(A ∩ B)

(ii) If A and B around mutually exclusive, then

P (‘A or B’) = P(A) + P(B)

i.e., P(A ∪ B) = P(A) + P(P) ∵ A ∩B = ϕ

(iii) If A is any event, then

P(‘not A’ ) = P(A’) = 1 – P(A)

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