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Degree of hardness of a water sample is 100ppm. If that sample contains hardness causing salt Mg(HCO_3)_2,calculate weight of Ca(OH)_2required for the treatment of 10kg of water sample. |
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Answer» Solution : Degree of hardness is 100ppm. Thus `10^(6)` g of HARD WATER contains 100g of `CaCO_(3)` which is equivalent to 146g of `MG(HCO_(3))_(2)` Weight of `Mg(HCO_(3))_(2)` present in 10kg of water `=(146xx10^(4))/(10^(6))=1.46g` `Mg (HCO_(3))_(2)+2CA(OH)_(2)to2CaCO_(3)+Mg(OH)_(2)+2H_(2)O` 146g of Mg`(148zxx1.46)/(146)=1.48g` |
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