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Degree of hydrolysis for a salt of strong acid and weak base isA. Independent of dilutionB. Increases with dilutionC. Increases with decrease in `K_(b)` of the basesD. Decreases with decrease in temperature |
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Answer» Correct Answer - B::C::D Let BA be this salt `BA to B^(+)+A^(-)` `A^(-)` does not undergo hydrolysis because HA is strong acid. `B^(+)` undergoes hydrolysis `B^(+) +H_(2)O=BOH+H^(+)` `h=sqrt((K_(h)V)/(c))-(1)h=` degreee of hydrolysis where `K_(h)= " Hydrolysis constant "= (K_(w))/(K_(b))` `h propsqrt(K_(h))-(3)` greater the `K_(b)` lesser the h `h propsqrtV-(4)V=` volume of salt solution hence h increases with dilution. `K_(h)=(K_(w))/(K_(b)). Both K_(w)and B_(b)` change with temperature, so `K_(h)` change with temperature. Hence, statement (b) is correct, h increases if `K_(b)` decreases, statement (c) correct. It is found that as temperatue, increases, `k_(w) and K+_(b)` increase but increase in `K_(w)` is greater than increase in `K_(b).` Hence, h increase with increase in temp. or h decreases with decrease in temp., hence statement (d) is correct, (a) is not correct from explanation of (b). |
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