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DeltaABC is given in adjacent diagram. P is mid-point of AC and Q is foot of perpendicular from origin tp AB `{:(,"Column-I",,"Column-II",,"Column-III",),((I),squareAQOP "is square",(i),P=((b)/(2),(b)/(2)),(P),"OQ=OP",),((II),DeltaOPQ "is an equilateral traingle",(ii),Q=(-(b)/(2),(b)/(2)),(Q),"AQ=AP",),((III),"OQ=QB",(iii),"OP=PC",(R),OP=(b)/sqrt(2),),((IV),AQ=QB",(iv),PC=OC,(R),OQ=b,):}` Which of the following is correct :A. `(II)(ii)P`B. `(I)(iiv)R`C. `(III)(iii)R`D. `(I)(iv)S` |
| Answer» Correct Answer - C | |