1.

DeltaG is net energy available to do useful work and is thus a measure of "free energy". Show mathematically that DeltaG is a measure of free energy. Find the unit of DeltaG. If a reaction has positive enthalpy change and positive entropy change, under what condition will the reaction be spontaneous ?

Answer»

Solution :Gibbs free energy is that thermodynamic quantity of a system, the decrease in whose value during a process is equal to the maximum POSSIBLE useful work that can be obtained from the system.
Mathematically, this results may be derived as follows :
The relationship between heat absorbed by a system Q, the change in its internal energy, `DeltaU` and the work done by the system is given by the equation of the first law of thermodynamics, therefore,
`q= Delta U + W_("expansion") + W_("non-expansion") ...(i)`
Under constant pressure condition, the expansion work is given by `pDeltaV`.
`therefore Delta U + p Delta V = W_("non-expansion")`
`= Delta H+ W_("non-expansion") ""...(ii)`
For a reversible change taking place at constant temperature,
`DeltaS= (q_("rev") )/( T) "or" q_("rev") = T Delta S""...(iii)`
Substituting the value of q from Eq. (iii) in Eq. (ii), we get
`T Delta S =Delta H + W_("non-expansion")`
OR `Delta H - T Delta S =- W_("non-expansion") ""...(iv)`
Substituting this value in equation (iv), we get
`DeltaG= - W_("non-expansion") ""...(v)`
THUS, free energy change can be taken as a measure of work other than the work of expansion.
For most changes, the work of expansion can not be converted to other useful work, whereas the non-expansion work is convertible to useful work.
Rearranging equation (v), it may be WRITTEN as
`-Delta G= W_("non-expansion")= W_("useful")`
As `- Delta G = W_("useful")` therefore, `Delta G` has the same units as those of work i.e., joule
`Delta G = Delta H - T Delta S`
If `Delta H = ` positive and `Delta S=` positive, then `DeltaG` will be negative i.e., process will be spontaneous only when `T DeltaS gt Delta H` in magnitude, which will be so when temperature is high.


Discussion

No Comment Found