1.

DeltaS_("says") "for" 4Fe_((s)) + 3O_(2) rarr 2Fe_(2) O_(3(s)) " is" -550 J//k//mol at 298K. If enthalpy change for same process is -1600kJ//mol, DS_("total") (in J/mol/K) is

Answer»

`[(1600)/(298) XX 10^(3)] + 550 GT 0`
`550- [(1600)/(298)[ lt 0`
`[(1600)/(298) xx 10^(3)] -550 gt 0`
`[(1600 + 550)/(298)] gt 0`

Solution :`Delta S_("total") = Delta S_("sys") + Delta S_("sourrounding") gt 0`
`= Delta S+ ((-Delta H)/(T)) = -550 + ((-(-1600))/(298) xx 10^(3))`
`= (1600)/(298) xx 10^(3) - 550 gt 0`


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