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Density of `2.05 M` solution of acetic acid in water is `1.02g//mL`. The molality of same solution is:A. `1.14 mol kg^(-1)`B. `3.28 mol kg^(-1)`C. `2.28 mol kg^(-1)`D. `0.44 mol kg^(-1)` |
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Answer» Correct Answer - C Mass of 1 litre solution of 2.05 M acetic acid = 1020 g Mass of acetic acid present in it = `2.05xx60=123 g` Mass of solvent (water) in this solution `= 1020-123 =897 g` `therefore` Molality of the solution `=(2.05)/(897)xx1000=2.28 mol kg^(-1)` |
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