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Density of `2.05 M` solution of acetic acid in water is `1.02g//mL`. The molality of same solution is:A. (a)0.44 mol `kg^(-1)`B. (b)1.14 mol `k^(-1)`C. (c )3.28 mol `kg^(-1)`D. (d)2.28 mol `kg^(-1)` |
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Answer» Correct Answer - D weight of acetic acid=`2.05xx60=123 g` Weight of solution`=1000xx1.02=1020 g` `:.` Weight of water`=(1020-123)=897 g` `:.` Molality`=(2.05xx1000)/897=2.285` |
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