Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is:

Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The

1.	Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is:
Answer» `1.14 mol KG^(-1)` `3.28 mol kg^(-1)` `2.28 mol K^(-1)` `0.44 mol kg^(-1)` Solution :Molality (m) `=M/(1000d - M M_(1)) xx 100` M = Molarity, MI = Molecular mass, d = density `therefore m=(2.05)/((1000 xx 1.02)-(2.05 xx 60)) xx 1000` `=2.28 mol kg^(-1)`