1.

Density of a gas is found to be 5.46 g//dm_(3) at 27 ^(@)C at 2 bar pressure. What will be its density at STP?

Answer»

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Solution :The molecular mass of a gas is given by `M=(dRT)/P`
Since, molecular mass does not change with temperature or pressure, in two different SETS of conditions, we have
`(d_1 RT_1)/P_1 =(d_2 RT_2)/P_2`
(given condition) (at S.T.P.)
or `(5.46 xx R xx 300)/2 = (d_2 xxRxx 273)/1`
or `d_2 =(5.46xx300)/(2xx273)=3 g/dm^3`


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