Density of a gas is found to be 5.46 g//dm^(3) at 27^(@)C at 2 bar pressure. What will be its density at STP ?

Density of a gas is found to be 5.46 g//dm^(3) at 27^(@)C at 2 bar pre

1.	Density of a gas is found to be 5.46 g//dm^(3) at 27^(@)C at 2 bar pressure. What will be its density at STP ?
Answer» Solution :where, `T_(1)=27^(@)C=(273+27)=300 K` `p_(1)=2 " bar," d_(1)=5.46 g//dm^(3)` STP is `T_(2)=273 K` Pressure `p_(2)=1.0` bar (New in method) Density `d_(2)=(?)` (In OLD method, STP means 1 atm = 1.01325) relation between density and pressure according to 5.32 equation. pM = dRT `therefore (p)/(td)=(R )/(M)=K` constant (`because` if there is only one gas value of R and M is not changed) `therefore (p_(1))/(T_(1)d_(1))=(p_(2))/(T_(2)d_(2))` `therefore ("2 bar")/((300 K)(5.46 g//dm^(3)))=("1.0 bar")/((273 K)(d_(2)))` `therefore d_(2)=("1.0 bar")/("2 bar")XX(300 K)/(273 K)xx5.46 g//dm^(3)` `= 2.029999 g//dm^(3)~~ 3.0 g//dm^(3)`