Density of ice is rho and thatof water is sigma .What will be from following decrease in volume when a mass M of ice melts ?

Density of ice is rho and thatof water is sigma .What will be from fol

1.	Density of ice is rho and thatof water is sigma .What will be from following decrease in volume when a mass M of ice melts ?
Answer» `(M)/(sigma-RHO)` `(sigma-rho)/(M)` `M[(1)/(rho)-(1)/(sigma)]` `(1)/(M)[(1)/(rho)-(1)/(sigma)]` Solution :VOLUME of ICE `V_(1)=(M)/(rho)` Volume of water `V_(2)=(M)/(sigma)` If `V_(1)gtV_(2)` , volume decreases for MELTING of ice . DECREASE in volume `=V_(1)-V_(2)=(M)/(rho)=(M)/(sigma)` `=M[(1)/(rho)-(1)/(sigma)]`