Depth of sea is maximum at Mariana Trench in West Pacific Ocean. Trench has a maximum depth of about `11km`. At bottom of trench water column above it exerts `1000 atm `pressure. Percentage change in density of sea water at such depth will be around (Given , B `= 2xx10^(9) Nm^(-2) and P_(atm) = 1xx10^(5 Nm^(-2)))`A. about `5%`B. about `10%`C. about `3 %`D. about `7 %`

Depth of sea is maximum at Mariana Trench in West Pacific Ocean. Trenc

1.	Depth of sea is maximum at Mariana Trench in West Pacific Ocean. Trench has a maximum depth of about `11km`. At bottom of trench water column above it exerts `1000 atm `pressure. Percentage change in density of sea water at such depth will be around (Given , B `= 2xx10^(9) Nm^(-2) and P_(atm) = 1xx10^(5 Nm^(-2)))`A. about `5%`B. about `10%`C. about `3 %`D. about `7 %`
Answer» Correct Answer - A Change in volume , `DeltaV = (-Delta_(p).V_(i))/B` Hence , density at depth of about `11 km ` is `= (Mass)/(Volume) = (rho_(o)xxV_(i))/(V_(i)-(Deltapv_(i))/B) = (rho_(o)B)/((B-Delta_(p)))` `=(rho_(o))/(1-Delta_(p)/B) = (rho_(o))/(1-(1xx10^(8))/(2xx10^(9)` `(rho_(o))/(1-(1)/(20))` = `= (rho)/(0.95) rArr rho = rho_(o)/0.95` ` rArr rho_(o) =0.95rho` `:.` % change in density `= (rho-rho_(o))/rho_(o)xx100` `= [(1/0.95-1)/1]xx100` ` ~~ 5%`

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