Derivations of equation of motion for uniform acceleration using graph

1.	Derivations of equation of motion for uniform acceleration using graphical method
Answer» G haa....... YashRajpootThakur1 id se..... u can search me on it......<br>hope its help you ☺<br>for 3 equation ...=> vbar=v+v0/2and from 1 equation =>t =v-v0/aso=>x=vbar×t=(v+v0/2)(v-v0/a)=v^2-v0^2/2a=>2a(x)=v^2-v0^2<br>for second equation , x = total area covered ...so .. x=area of reactangle+area of triangle ...=> l×b+1/2base×height => v0×t+1/2(t)(v-v0)from 1 equation we get .......=> v0t+1/2(t)(atL=> v0t+1/2at^2<br>for 1 equation => a=v-v0/t => at=v-v0 => v=v0+at<br>Tum log brainly per ho??<br>Arey yr.... yhaa pr kaise du answer.....Brianly app pr add kr question uss pr dunga yhaa nhi..... ho payega

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