Saved Bookmarks
| 1. |
Derive a Canonical POS expression for a Boolean function G, represented by the following truth table:XYZG (X, Y, Z)00010010010101111000101111011110 |
|
Answer» POS =x'y'z' + x'yz' +x'yz+ xy'z + xyz' =∑m(0,2,3,5,6) |
|