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Derive all formula for propulison of rocket |
Answer» Let us consider, rocket of mass m0\xa0take off with velocity v0\xa0from ground. Let the fuel burnt at the rate of dm/dt and burnt gases eject with velocity u w.r.t. rocket.Let at any instant t, v be the velocity of rocket and m be the mass of rocket. Therefore velocity of burnt gas ejected w.r.t. ground is (v – u). As the fuel burns at the rate of dm/dt, therefore in time dt, dm mass of the fuel will burn and velocity of rocket increases by dv.Here m is the mass of rocket and dm is the mass of gas ejected. As the fuel burns the mass of rocket decreases. Therefore, to calculate the velocity of rocket at any instant in terms of mass of rocket, dm must be replaced by ‘dm’.\xa0 | |