Derive an expression for excess pressure inside the a soap bubble

1.	Derive an expression for excess pressure inside the a soap bubble
Answer» Expression for Excess pressure inside the soap bubble....=> F-inside = Force-outside +(T×2πr)×2...=>P(inside)×(πr^2)=P(outside)×(πr^2)=> Cancel out whatever is being cancelled...=> P(inside)=P(outside)+4T/R=> P(excess)= Pi -Po=4T/R.......Hope this helps uh...<br>4T/R

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