Derive an expression for range of a projectile and for what angle of p

1.	Derive an expression for range of a projectile and for what angle of projection horizontal range becomes maximum?
Answer» Maximum horizontal range :- sin 2theta = 1 sin 2theta = sin 90° theta = 45° R = u² sin2 (45°)/g R = u² sin 90° /g R = u²/g

Derive an expression for range of a projectile and for what angle of projection horizontal range becomes maximum?

Answer»

Maximum horizontal range :-

sin 2theta = 1

sin 2theta = sin 90°

theta = 45°

R = u² sin2 (45°)/g

R = u² sin 90° /g

R = u²/g

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Derive an expression for range of a projectile and for what angle of projection horizontal range becomes maximum?

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