1.

Derive an expression for the kinetic energy of an object.

Answer» K=1/2mv^2
Consider a body of mass m initially at rest. If on application of force F, it travels a distance s, thenWork done, W = F x sBy Newton\'s second law, F = maW = ma x swhere, a = accelerationUsing equation of motion v2 - u2 =2as, we get(v2-u2)/2 = asW = m x (v2 - u2)/2As intial velocity is zero, W = ½mv2This work done is stored as kinetic energy of the object.So, KE = ½ mv2


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