Derive an expression for the rate of flow of a liquid through a capillary tube. Assume that the rate of flow depends on (i) pressure gradient ((P)/(l)), (ii) The radius, r and (iii) the coefficient of viscosity, eta. The value of the proportionally constant k= (pi)/(8).

Derive an expression for the rate of flow of a liquid through a capill

1.	Derive an expression for the rate of flow of a liquid through a capillary tube. Assume that the rate of flow depends on (i) pressure gradient ((P)/(l)), (ii) The radius, r and (iii) the coefficient of viscosity, eta. The value of the proportionally constant k= (pi)/(8).
Answer» <P> Solution :`(V)/(t)= k ((p)/(l) (r^(4))/(eta))= (pi)/(8) ((PR^(4))/(1 eta)) [ because k= (pi)/(8)]`