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Derive Boyle’s law on the basis of kinetic theory of gases. |
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Answer» According to kinetic theory, pressure, P exerted by a gas is \(P=\frac{1}{3}ρv^2\) \(=\frac{1}{3}(\frac{M}{V})v^2\) ∴ PV = \(\frac{1}{3}Mv^2\) But at constant temperature total K.E. of gas \(\frac{1}{3}\) (M/V)v2 or v2 will be constant. ∴ At a constant temperature, PV = constant. |
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