1.

Derive Boyle’s law on the basis of kinetic theory of gases.

Answer»

According to kinetic theory, pressure, P exerted by a gas is

\(P=\frac{1}{3}ρv^2\)

\(=\frac{1}{3}(\frac{M}{V})v^2\)

∴ PV = \(\frac{1}{3}Mv^2\)

But at constant temperature total K.E. of gas \(\frac{1}{3}\) (M/V)v2 or v2 will be constant.

∴ At a constant temperature, PV = constant.



Discussion

No Comment Found

Related InterviewSolutions