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Derive Charles’s law on the basis of kinetic theory of gases. |
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Answer» According to kinetic theory of gases, pressure of a gas, \(P=\frac{1}{3}.ρv^2\) \(=\frac{1}{3}\frac{M}{V}v^2\) \(P=\frac{1}{3}.\frac{M}{V}v^2\) For a given mass of a gas at constant pressure P, we have V ∝ v2 According to kinetic theory, V2 ∝ T so, V ∝ T This proves Charles’s law. |
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