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Derive equation for heat flow rate in rectangular block of solid. |
Answer» Solution :Figure shows a rectangular block of solid of cross section .A..  Let us consider two cross sections ABCD and EFGH, at a distance x and `Deltax` from one end of a block having temperature `T+DeltaT` and T respectively. Here, the distance between two cross section is `Deltax` and temperature difference is `DeltaT`. The ratio `DeltaT//Deltax` is called temperature gradient Temperature gradient : The difference in temperature per unit distance between two parts of a solid is called distance between two parts of a solid is called as temperature gradient parts of a solid is called as temperature gradient. Its unit is Kelvin/meter and dimensional formula is `M^(0)L^(-1)T^(0)K^(1)`. Experiment shown that for a small change in temperature, the amount of heat passing between these two cross sectional planes in direction perpendicular to these planes in time `Deltat` DEPENDS on the following factors : `DeltaQprop(DeltaT)/(Deltax)"(For given "Deltat" and A)"` `DeltaQpropDeltat" (For given "DeltaT//Deltax" and A)"` `DeltaQpropA" For given "Deltat " and "DeltaT//Deltax")"` `:.DeltaQ=-kA(DeltaT)/(Deltax)Deltat` `(DeltaQ)/(Deltat)=-kA(DeltaT)/(Deltax)` . . .(1) Here, k is constant of proportionality called THERMAL conductivity of the material of the block. Its VALUE depends on the type of the material and to some extent on the temperature. The materials with higher value of thermal consuctivity are good conductors of heat. Normalally, if the differnces in the temperatures of different parts of solid are not very large, k can be considered a constant. Negative sign in above equation indicates that with the increase in x the temperature decreases. Taking limits `Deltax to 0` and `Deltat to0` in equation (1) `(dQ)/(dt)=-kA(dT)/(dx)`. . . (2) `:.H=-ka(dQ)/(dt)` `(dQ)/(dt)=H` is called heat current. Heat current is the RATE of flow of heat through any cross section. Its unit is cal/s or J/s, its dimensional formula is `M^(1)L^(2)T^(-3)`. |
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