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Derive expression projectile motion and find time period, rangeand height of projectile. |
Answer» For vertical projectile equation are as follow: 1) time period is 2usin(thita)/g.ii) range is u to the power 2 /g*sin2thita.iii) height is u to the power 2*sin to the power 2thita/2g.iv) trajectory path is xtan thita - 1/2*g*xto the power 2/u to the power 2*(sec thita) | |