Saved Bookmarks
| 1. |
Derive relation between density of gases and molecular mass by using of Avogadro.s law. |
|
Answer» Solution :CALCULATION of moles of gas : Gaseous mole `(n)=("Weight of gas (gm)n")/("MOLECULAR mass of gas (M)")` `therefore n = (m)/(M) ""`…..(Eq. - i) where, m = weight of gas M = molecular mass of gas According to Avogadro law of formula : `V = k_(4) n ""`.....(Eq. - ii) `therefore V = k_(4)(m)/(M) ""`...(Eq. - iii) Thus, `M=k_(4)((m)/(V)) ""`......(Eq. -iv) but, `(m)/(V)=` density of gas = d `therefore M = k_(4)d ""`.....(Eq. -v) DERIVATION : ..Density of gas is directly proportional to its molecular mass... |
|