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Derive the effective resistance of three resistors R 1 , R 2 & R 3 when connected in series, with the help of a labelled diagram. |
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Answer» 10.33 ΩExplanation:Derivation for effective resistance is series.In series combination : CURRENT i is same in all resistancePotential difference isn't same!= > V = V₁ + V₂ + V₃ ... ( i )Let we have three resistors R₁ , R₂ and R₃From ohm's law we know : V = I R= > Using for ( i ) we GET : I R_e = I R₁ + I R₂ + I R₃= > R_e = R₁ + R₂ + R₃Now finding effective resistance given in question : Here 5 Ω and 10 Ω are in parallel : R_net = R₁ R₂ / R₁ + R₂R_e = 7 + ( 50 / 15 ) = > R_e = ( 105 + 50 ) / 15= > R_e = 155 / 15 Ω = 10.33 ΩHence we get required ANSWER! |
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