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Derive the equation of motion s=ut+1/2at^2 by graphically |
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Answer» E!!!!!..At t = 0, initial velocity = u = OA At t = t, final velocity = v = OC The DISTANCE S TRAVELLED in time t = area of the trapezium OABD s = (1/2) x (OA + DB) × OD s = (1/2) x (u + v) × t Since v = u + at, s = (1/2) x (u + u + at) × t s = ut + (1/2) at2..PLZ MARK IT BRAINLIEST ANSWER!! |
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