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Derive the equations of motion for a particleFalling vertically |
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Answer» Solution :A body filling from a height h :Let us consider an object of mass m falling from a height 'h . Let us assume there is no air resistance, The object EXPERIENCES acceleration 'g' due to GRAVITY that is constant. a = g If the particle is thrown with initial VELOCITY 'u' downward that is in NEGATIVE - Y-aixs, then velocity and position of the particle at any time t is given by v = u + gt. . . (1) `y = ut +(1)/(2) g t^(2)"". . . (2)` When it is at a distance y from the hill -top , is `v^(2) = u^(2) +2gy "". . . (3)` Suppose the particle starts from rest. u = 0 For a point y from the hill -top v = gt ` y = (1)/(2) g t^(2)` `v^(2) = 2 gy` 
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