1.

Derive the expression for gravitational potential energy.

Answer»

Solution :The gravitational potential DUE to mass `m_(1)` at a POINT P which is at a distance r from `m_(1)` is obtained by making `m_(2)` equal to unity (`m_(2)` = 1kg). THUS the gravitational potential V® due to mass `m_(1)` at a distance r is
`V(r)=-(Gm_1)/(r)`


Discussion

No Comment Found