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Derive the expression Kb = [M+ ][OH- ] / [MOH] for dissociation of a weak base MOH in water , which is undergo complete dissociation in the solution. |
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Answer» MOH -----> M+ + OH- Initial conc Cx1 0 0 C-Cα Cα Cα Kb = [H+ ][X- ] / [HX] = Cαx Cα/C- Cα =C2 α2 /C(1-α) Kb=Cα2 /1-α |
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