1.

Derive the expression Kb = [M+ ][OH- ] / [MOH] for dissociation of a weak base MOH in water , which is undergo complete dissociation in the solution.

Answer»

MOH -----> M+ + OH-

Initial conc Cx1       0      0 

                  C-Cα    Cα    Cα 

                     Kb = [H+ ][X- ] / [HX]

                          = Cαx Cα/C- Cα 

                          =C2 α2 /C(1-α) 

                           Kb=Cα2 /1-α



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