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1. |
Derive the Kp and Kc relations for the reaction.PCl5(g) ⇋ PCl3(g) + Cl2(g) |
Answer» PCl5(g) ⇋ PCl3(g) + Cl2(g) KP = KC(RT)∆n ∆n = nP – nR = 2 – 1 = 1 ∆n = +Ve ∴ KP > KC |
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