1.

Derive the Kp and Kc relations for the reaction.PCl5(g) ⇋ PCl3(g) + Cl2(g) 

Answer»

PCl5(g) ⇋ PCl3(g) + Cl2(g) 

KP = KC(RT)∆n

∆n = nP – nR = 2 – 1 = 1

∆n = +Ve

∴ KP > KC



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