Derive the reaction between K_pand K_c in these three reactions.(a)N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) (b)2SO_(2(g)) + O_(2(g)) hArr 2SO_(3(g)) (c) N_2O_(4(g)) hArr 2NO_(2(g))

Derive the reaction between K_pand K_c in these three reactions.(a)N_(

1.	Derive the reaction between K_pand K_c in these three reactions.(a)N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) (b)2SO_(2(g)) + O_(2(g)) hArr 2SO_(3(g)) (c) N_2O_(4(g)) hArr 2NO_(2(g))
Answer» Solution :(a)`Deltan_((g))`=2-1-3=-2 therefore `K_p=K_c (RT)^(-2)` THUS, `Deltan_((g))` = negative number So, `K_p LT K_c` (b)`Deltan_((g))`=2-2-1=-1 therefore `K_p=K_c(RT)^(-1)` Thus, `Deltan_((g))`=negative number So, `K_p lt K_c` (c) `Deltan_((g))`=(2-1)=1 therefore `K_p =K_c (RT)^(+1)` Thus, `Deltan_((g))`=POSITIVE number So, `K_p gt K_c`