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Derive the relation between Ka and Kb. |
Answer» Welcome ???<br>Thnk u??<br>Looks like??<br>My answer is correct or not<br>The Ka is the acid dissociation constant of a weak acid, and the Kb is the dissociation constant of its conjugate base. Alternatively, we can also say, Kb is the base dissociation constant of a weak base, and Ka is the dissociation constant of its conjugate acid.We can deduce the same relationship, i.e. Ka⋅Kb=Kw, for these cases also. Without loss of generality, let the weak acid be HA and its conjugate base is A− (you can also do the same [not identical] derivation considering base B and its conjugate acid BH+).Considering acid dissociation,HA↽−−⇀H++A−Ka=[H+][A−][HA],and for the basic action of its conjugate base, consider,A−+H2O↽−−⇀HA+OH−Kb=[HA][OH−][A−].Multiplying both the equations, we will have,Ka⋅Kb=[A−][H+][HA]⋅[HA][OH−][A−]=[H+][OH−]=KwSo, it is proved that for any acid/conjugate base pair (or, base/conjugate acid pair) the identical relation, Ka⋅Kb=Kw holds. Hope this answer will help u?????? | |