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Derive the relationship between C_(p) and C_(v)for an ideal gas. |
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Answer» SOLUTION :Relation between Cp and Cv for an ideal gas .From the definition of enthalpy `H = U + PV "" . . . . (1)` For 1 mole of an ideal gas `PV = NRT "" . . . . (2)` By substituting (1) in (2) `H = U + nRT "" . . . . (3)` DIFFERENTIATING the above equation with respect to ` T , (del H)/(delT) = (delU)/(delT) + "nR"(delT)/(delT)` ` [ :' ((delH)/(delT))_(p)=D_(p)and ((delU)/(delT))_(v)=C_(V)]` `C_(p) = C_(v) +nR` `C_(p) - C_(v) = nR` |
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