InterviewSolution
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Derive the relationship between molar conductance and equivalent conductance of an electrolyte. |
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Answer» Equivalent conductivity (Λ): The conductance of that volume of solution containing one equivalent of an electrolyte is known as equivalent conductivity. It is denoted by Λ. Let us consider the V cm3 of solution containing one equivalent of an electrolyte. Its conductance is equal to equivalent conductance, Λ. Also we know that the conductance shown by 1 cm3 solution containing this electrolyte is called specific conductance, κ. i.e., the conductance of V cm3 --------- Λ the conductance of 1 cm3 --------- κ Therefore: Λ = κ.V ---------- equation (3) We know that the normality (N) of a solution is given by the equation: N = ne/V(in cc) x 1000 For above electrolytic solution, no. of equivalents, ne = 1. Hence V(in cc) = 1000/N By substituting the above value in the equation (3), we can now write: Λ = k 1000/N Units of Λ: = Ohm-1 cm-1/ equivalents cm3 = cm2 . ohm-1 . equiv-1 = cm2 . mho. equiv-1 or m2 . Siemens. equiv-1 Molar conductivity (Λm or μ): The conductance of that volume of solution containing one mole of an electrolyte is known as molar conductivity. It is denoted by Λm or μ. It is related to specific conductance, κ as: μ = κ.V or μ = k 1000/M Where M = molarity of the electrolytic solution. Units of μ: = cm2 . ohm-1 . mol-1 = cm2 . mho. mol-1 or m2 . Siemens. mol-1 The relation between equivalent conductance, Λ and molar conductance, μ can be given by: μ = Λ x equivalent factor of the electrolyte |
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