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Derive v=u + at and v2 = u2 + 2as graphically. |
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Answer» graph for derivation we know : displacement = area under the velocity time graph . S= area of trapezium ACEF S= 1/2 ( b¹ + b² ) h s= 1/2 ( AF+CE )FE S= 1/2 ( U+ V) T We know -v= u+ at v-u/a= t now 2 in 1 S= 1/2( v+u) (v-u) 2as= ( v+u) (v-u) 2as=v²-u² [v² - u2 = 2as] HOPE it will help uExplanation: |
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