1.

Derive v=u + at and v2 = u2 + 2as graphically.​

Answer» <html><body><p>graph for derivation we know : displacement = area under the velocity time graph . S= area of trapezium ACEF S= <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>/2 ( b¹ + b² ) h s= 1/2 ( AF+CE )<a href="https://interviewquestions.tuteehub.com/tag/fe-460008" style="font-weight:bold;" target="_blank" title="Click to know more about FE">FE</a> S= 1/2 ( <a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>+ <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>) T We know -v= u+ at v-u/a= t now 2 in 1 S= 1/2( v+u) (v-u) 2as= ( v+u) (v-u) 2as=v²-u² [v² - u2 = 2as] <a href="https://interviewquestions.tuteehub.com/tag/hope-25911" style="font-weight:bold;" target="_blank" title="Click to know more about HOPE">HOPE</a> it will help uExplanation:</p></body></html>


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