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| 1. |
Describe rutherford experiment? |
| Answer» Rutherford’s Scattering Experiment:\xa0Rutherford selected a gold foil as he wanted a very thin layer. The gold foil used by Rutherford was 0.004 millimetres in thickness. That is, the foil was about 1000 atoms thick. In his experiment, fast moving α-particles (alpha particles) were made to fall on a thin gold foil. The α-particles are helium ions with a+2 charge. Their atomic mass is 4 u. Hence, a high velocity beam of α-particles has a lot of energy. These particles were studied by means of flashes of light they produced on striking a zinc sulphide screen. The α-particles are much heavier than the sub-atomic particles present in gold atoms.\xa0Hence, he expected the α-particles to pass through the gold foil with little deflection and strike the fluorescent screen. But the observations he made were quite unexpected. | |