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Describe the change in hybridisation (if any) of the Al in the following reaction. AlCl_(3)+Cl^(-) to AlCl_(4)^(-) |
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Answer» SOLUTION :USING the equation, `H=(1)/(2)[V+X-C+A]` In `AlCl_(3),H=(1)/(2)(3+3-0+0)=3` `therefore `Hybrid state of Al=`sp^(2)` In `[AlCl_(4)]^(-),H=(1)/(2)(3+4-0+1)=4` `therefore` Hybrid state of Al=`sp^(3)` |
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