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Describe the change in hybridisation (if any) of the `AI` atom in the following: `AlCl_(3)+Cl^(ө)rarr AlCl_(4)^(ө)` |
Answer» In `AlCl_(3),` the central Al atom is `sp^(2)` hybridised while in the ion `[AlCl_(4)]^(-),` it has `sp^(3)` hybridisation. `underset(H=1//2[3+3-0+0]=3(sp^(2)))(AlCl_(3))" "underset(H=1//2[3+4-0+1]=4(sp^(2)))([AlCl_(4)]^(-))` |
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