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Describe the change in hybridization (if any) of the Al atom in the following reaction. AlCl_(3) + Cl^(-) rarr AlCl_(4)^(-1) |
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Answer» Solution :No CHANGE in hybridization of AL. In monomolecular `AlCl_(3)` Al has `sp^(2)` hybridization which change `sp^(3)` in `AlCl_(4)^(-1)` but `AlCl_(3)` EXIST as timer `Al_(2)Cl_(6)` molecule so Al has hybridization `sp^(3)`. In `AlCl_(4)^(-1)` Al has `sp^(3)` hybridization. So no change. |
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