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Describe the effect of: (a) addition of H_2 (b) addition of CH_3OH (c) removal of CO (d) removal of CH_3OH on the equilibrium of the reaction : 2H_(2(g)) + CO_((g)) hArr CH_3OH_((g)) |
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Answer» Solution :Reaction : `2H_(2(g)) +CO_((g)) HARR CH_3OH_((g))` (a)`H_2` is reactant, so to DECREASES the effect of added `H_2` the forward reaction occurs and the product `CH_3OH` is increases. (b) `CH_3OH` is added : Reaction CONSUME `CH_3OH` so moves in reverse direction. (c) CO is removed : CO is reactant so if the CO is removed than reaction moves in reverse direction and product `CH_3OH` decreases. (d) `CH_3OH` is removed : Than reaction try to FORM `CH_3OH`so move in forward direction. |
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