InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Describe the motion of a particle acted upon by a force (i) `F= -2(x - 2)^(3)` (ii) `F= -2(x - 2)^(2)` (iii) `F= -2(x - 2)` |
|
Answer» Correct Answer - A (i) `F= -2(x - 2)^(3)` `F = 0` at `x = 2` Force is along negative x-direction for `x > 2` and it is along positive x-direction for `x < 2`. Thus, the motion of the particle is oscillatory ( but not simple harmonic ) about `x = 2`. (ii) `F = 0` for `x = 2`, but force is always along negative x-direction for any value of `x` except at `x = 2`. Thus, the motion of the particle is rectilinear along negetive x-direction provided it is not kept at rest at `x = 2`. (iii) Let, us take `x - 2 = X`, then the given force can be written as, `F = -2X` This is the eqation of SHM. Hence, the particle oscillates simple harmonically about `X=0` or `x = 2`. |
|