Saved Bookmarks
| 1. |
Describe the shapes of BF_3 and BH_4^- . Assign the hybridisation of boron in these species. |
Answer» Solution :(i)`BF_3`: As a result of its small size and high electro-negativity, boron TENDS to form monomeric covalent halides. These halides have a planar triangular geometry. This triangular shape is FORMED by the overlap of THREE `sp^2` hybridised orbitals of boron with the sp orbitals of three halogen atoms. Boron is `sp^2` hybridised in `BF_3`. (ii) `BH_4^-` : Boron-hydride ION `(BH_4^-)` is formed by the `sp^3` hybridisation of boron orbitals. Therefore, it is TETRAHEDRAL in structure.
|
|